How do you reverse an 8 bit number?

How do you reverse an 8 bit number?

Reverse an 8 bits number | 8085 Microprocessor

  1. Load the accumulator with the first data.
  2. Use RLC instruction to shift contain of accumulator by 1 bit without carry. Use this 4 times to reverse the contain of accumulator.
  3. Now load the result value in memory location.

How can I reverse 16 bit number in 8085?

Problem – Write an assembly language program in 8085 microprocessor to reverse 16 bit number….Program –

2008 MOV L, A L <- A
2009 MOV A, H A <- H
200A RLC Rotate accumulator content left by 1 bit without carry
200B RLC Rotate accumulator content left by 1 bit without carry

Which instruction is used to obtain the 16 bit number from 8 bit number?

Problem – Write an assembly language program in 8086 microprocessor to divide a 16 bit number by an 8 bit number….Program –

0409 MOV AX, [SI] AX <- [SI]
040B DIV BL AX <- AX / BL
040D MOV [DI], AX [DI] <- AX
040F HLT End of program

What is RAL in microprocessor?

In 8085 Instruction set, there is another mnemonic RAL,which stands or Rotate Accumulator Left and also involving Cy flag in rotation. It rotates the Accumulator contents to the left by 1-bit position. The instruction can be used for multiple purposes.

Can we store a 16 bit numbers in a memory location in 8085?

The 16-bit numbers are stored into memory location 8001H onwards. The value of N is stored at location 8000H. After addition, the result will be stored at location 8050H onwards. In 8085 we have few number of registers.

Which bit of 8-bit and 16-bit number is used to decide if the number is positive or negative?

bit is zero, the number is positive; if the H.O. bit is unique, the number will be negative. Examples:For 16-bit numbers:$8000 is negative because the H.O. bit is one.

How does the 8086 processor identify between 8-bit and 16-bit operations?

The bit size (8-bit, 16-bit, 32-bit) of a microprocecessor is determined by the hardware, specifically the width of the data bus. The Intel 8086 is a 16-bit processor because it can move 16 bits at a time over the data bus. The Intel 8088 is an 8-bit processor even though it has an identical instruction set.

What does DAA instruction do in 8085?

Detailed Solution. DAA means decimal adjust accumulator and it is used in BCD addition. DAA instruction changes the binary values of contents of the accumulator to BCD.

Which flag is present in 8085 microprocessor?

8085 has five flags. Sign flag, zero flag, Auxiliary carry flag, Parity flag and Carry flag. A 8-bit register is used to represent five flags as shown in following figure.

How will 8-bit data get stored in the HL pair?

As HL pair has to be stored, so it has to be stored in two consecutive locations starting at the address a16. So their contents will be stored in two consecutive memory locations as each memory location can hold 8-bits of data. This instruction uses absolute addressing mode for specifying the destination.

What is 8085 instruction set?

Data Transfer Group

Instruction Set Explanation Machine Cycles
MOV M, r [[H-L]]←[r] Move the content of register to memory 2
MVI r, data [r] ←data Move immediate data to register 3
LXI rp, data 16 [rp] ←data 16 bits, [rh] ←8 MSBs, [rl] ←8 LSBs of data Load Register pair immediate 3
LDA addr [A] ←[addr] Load Accumulator direct 4

What is an 8-bit number?

8 bits, can represent positive numbers from 0 to 255. hexadecimal. A representation of 4 bits by a single digit 0..

Share this post